(4/k-2)^2-2(k-2/k-2)=7

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Solution for (4/k-2)^2-2(k-2/k-2)=7 equation: 



(4/k-2)^2-2(k-2/k-2)=7

We move all terms to the left:

(4/k-2)^2-2(k-2/k-2)-(7)=0



Domain of the equation: k-2)^2!=0

k∈R





Domain of the equation: k-2)!=0

k∈R



We multiply parentheses

(4/k-2)^2-2k+4k+4-7=0

We multiply all the terms by the denominator


(4-2k*k-2)^2+4k*k-2)^2+4*k-2)^2-7*k-2)^2=0

We add all the numbers together, and all the variables

(-2k*k+2)^2+4k*k-2)^2+4*k-2)^2-7*k-2)^2=0

Wy multiply elements

4k^2+(-2k*k+2)^2-2)^2+4*k-2)^2-7*k-2)^2=0

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